Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
namun | 148 | 12 | 1 | 12.0000 |
Dalam | 185 | 10 | 1 | 10.0000 |
paling | 122 | 9 | 1 | 9.0000 |
lahir | 134 | 13 | 2 | 6.5000 |
secara | 272 | 18 | 3 | 6.0000 |
7 | 46 | 5 | 1 | 5.0000 |
jatuh | 34 | 5 | 1 | 5.0000 |
Dewan | 43 | 5 | 1 | 5.0000 |
hingga | 202 | 9 | 2 | 4.5000 |
terbesar | 75 | 4 | 1 | 4.0000 |
km | 44 | 4 | 1 | 4.0000 |
cukup | 57 | 4 | 1 | 4.0000 |
Wikipedia | 44 | 4 | 1 | 4.0000 |
jiwa | 121 | 4 | 1 | 4.0000 |
berwarna | 35 | 4 | 1 | 4.0000 |
Serikat | 98 | 4 | 1 | 4.0000 |
asing | 23 | 4 | 1 | 4.0000 |
informasi | 31 | 4 | 1 | 4.0000 |
nasional | 60 | 4 | 1 | 4.0000 |
Provinsi | 74 | 7 | 2 | 3.5000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
udara | 56 | 1 | 7 | 0.1429 |
jenis | 77 | 1 | 7 | 0.1429 |
menghasilkan | 66 | 1 | 6 | 0.1667 |
bentuk | 98 | 1 | 6 | 0.1667 |
raja | 51 | 1 | 5 | 0.2000 |
diketahui | 49 | 1 | 5 | 0.2000 |
demikian | 54 | 1 | 5 | 0.2000 |
presiden | 60 | 1 | 5 | 0.2000 |
zaman | 55 | 1 | 5 | 0.2000 |
Maret | 66 | 2 | 9 | 0.2222 |
waktu | 119 | 2 | 9 | 0.2222 |
kekuasaan | 44 | 1 | 4 | 0.2500 |
memperoleh | 41 | 1 | 4 | 0.2500 |
sepak | 49 | 1 | 4 | 0.2500 |
sedang | 68 | 1 | 4 | 0.2500 |
pasukan | 78 | 1 | 4 | 0.2500 |
pun | 88 | 1 | 4 | 0.2500 |
bumi | 45 | 1 | 4 | 0.2500 |
asli | 33 | 1 | 4 | 0.2500 |
India | 64 | 1 | 4 | 0.2500 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II